Reflection: Grappling with Complexity How Many Fence Panels? - Section 3: Guided Practice


Looking back on this lesson, I now realize that I could have demonstrated how to solve the more complex problems using an easier model. 

For example, I could have showed shown how a 2 ft panel x 2 ft panel = 4 square feet & 4 panels.

Then I could have asked: What if I wanted a space with 8 square feet? 

We could all draw two "2 x 2 squares." (2 x 4 = 8 square feet & 6 panels). This is also a 2(2x2).

What if we wanted a space with 12 square feet? 

We could all draw three "2 x 2 squares." (2 x 6 = 12 square feet & 8 panels). This is also a 3(2x2).

By looking at each rectangle this way, I could have helped strengthen student understanding of the distributive property. 

2 x 2

2 ( 2 x 2 )

3 ( 2 x 2 )

After this, I could have challenged students to find the number of panels needed for 72... 108... 144 square feet. 

  Grappling with Complexity: Modeling
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How Many Fence Panels?

Unit 14: Area & Perimeter
Lesson 14 of 19

Objective: SWBAT determine the perimeter of a dog pen when the area is specified.

Big Idea: Students will explore the number of six-foot fence panels needed to construct a dog pen with a given area.

  Print Lesson
Math, Geometry, Geometric Modeling, area (Measurement), perimeter (Determining Measurements), perimeter, area of rectangle, fencing, dog pens
  95 minutes
white board problem solving
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